# Line slope calculator 6x+5y=52

**Straight line given by points A[2; 8] and B[7; 2]**

## Calculation:

**Slope-intercept form of line:**y = -1.2x+10.4

**Canonical form of the line equation:**6x+5y-52 = 0

**Parametric form of the line equation:**

x = 5t+2

y = -6t+8 ; t ∈ R

**Slope:**m = -1.2

**Slope angle of line: φ =**-50°11'40″ = -0.8761 rad

**X intercept:**x

_{0}= 8.6667

**Y intercept:**y

_{0}= q = 10.4

**Distance line from the origin:**d

_{0}= 6.6579

**The length of the segment AB: |AB| =**7.8102

**Vector: AB =**(5; -6)

**Normal vector: n =**(6; 5)

**Midpoint of the segment AB: M =**[4.5; 5]

**Perpendicular Bisector equation:**5x-6y+7.5 = 0

**Vector OA = (2; 8) ; |OA| = 8.2462**

**Vector OB = (7; 2) ; |OB| = 7.2801**

**Scalar product OA .OB = 30**

**Angle ∠ AOB = 60°1'6″ = 1.0475 rad**